ploting 2d graph of a vector

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adam hafzadi
adam hafzadi 2021-5-14
编辑： adam hafzadi 2021-5-15
Hey Friends,
I am trying to plot a vecotr (a solution of deritinal eqution) somting like those:
x(t)=Aexp(-3t)
y(t)=Bexp(2t)
Where A B are contecst ( so i am trying to see serveral function)
thanks a lot, Adam.

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采纳的回答

Chad Greene
Chad Greene 2021-5-14
Ran in:
You've pretty much got it, but you'll need to define a range of t values, and a value for the constants A, and B. You also need to use the * symbol for multiplication.
t = 0:0.1:10; % a range of t values from 0 to 100, steps of 0.1
A = 1;
B = 2;
x=A*exp(-3*t);
y=B*exp(2*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')
You may also want to set the vertical scale to log scale:
set(gca,'yscale','log')

更多回答（1 个）

adam hafzadi
adam hafzadi 2021-5-14
oh thank you , but when i am trying to do somtig more seresis its dosn`t work
t = -100:0.1:100; % a range of t values from 0 to 100, steps of 0.1
A = 1;
B = 2;
x=A*exp(-2*t)+B*t*exp(-2*t);
y=A*exp(2*t)+B*t*exp(-2*t)+B*exp(-2*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')
  2 个评论
Chad Greene
Chad Greene 2021-5-14
Ran in:
Oh, yes, that's a quirk of Matlab when you multiply or divide vectors. By default Matlab tries to do a "cross multiplication". To do "dot multiplication" instead, just put a period (.) in front of every multiplication symbol, like this:
t = -100:0.1:100; % a range of t values from -100 to 100, steps of 0.1
A = 1;
B = 2;
x=A.*exp(-2.*t)+B.*t.*exp(-2.*t);
y=A.*exp(2.*t)+B.*t.*exp(-2.*t)+B.*exp(-2.*t);
plot(t,x)
hold on
plot(t,y)
legend('x(t)','y(t)')

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