Find repeated values in an array, by column and rows (unique function).

Hi, I want to find the repeated vectors in an array where I have n columns and m rows. For example in the following array:
ARRAY = [
9.04828 8.80036 ...
9.04828 8.80036 ...
9.11259 8.74653 ...
9.04828 8.80036 ...
9.24358 8.74653 ...
8.9823 9.05449 ...
9.02563 8.24793 ...
7.5415 8.94942 ...
7.28989 8.81836 ...
...
]
I want to find the repeated vectors (x1, x2), which are repeated in rows 1, 2 and 4. Using the unique function, I can get the repeated value by defining:
[C1, ia1, ic1] = unique(A(:,1),'stable', 'rows');
but only by columns. How can I get the vector that repeats?
Thanks in advance.

 采纳的回答

A = [9.04828 8.80036 ;
9.04828 8.80036 ;
9.11259 8.74653 ;
9.04828 8.80036 ;
9.24358 8.74653 ;
8.9823 9.05449 ;
9.02563 8.24793 ;
7.5415 8.94942 ;
7.28989 8.81836 ] ;
[C1, ia1, ic1] = unique(A,'stable', 'rows');
A(ic1==1,:)

3 个评论

Hi KSSV, it works, now knowing that there are repeated values, how can I remove it from the initial array, leaving only one?
Thanks in advance.
You have it caluclated from the function already..... C1 is the array you want.
Thank you very much for your help.
Best regards.

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更多回答(1 个)

A = [9.04828 8.80036 ;
9.04828 8.80036 ;
9.11259 8.74653 ;
9.04828 8.80036 ;
9.24358 8.74653 ;
8.9823 9.05449 ;
9.02563 8.24793 ;
7.5415 8.94942 ;
7.28989 8.81836 ] ;
C=num2cell(A,1);
[G,ID{1:2}]=findgroups(C{:});
ID=cell2mat(ID)
ID = 7×2
7.2899 8.8184 7.5415 8.9494 8.9823 9.0545 9.0256 8.2479 9.0483 8.8004 9.1126 8.7465 9.2436 8.7465

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