Sort fields of struct by length and alphabetically

Question

Michel C 2021-5-20

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https://ww2.mathworks.cn/matlabcentral/answers/834988-sort-fields-of-struct-by-length-and-alphabetically

评论： KAE 2021-8-20

I've been trying to sort the fields of a struct by combination of length and name. Length should take precedence, but if the length of two or more fields is equal (for example if they are scalar), those should be sorted alphabetically (within that group), where names starting with capital letter should take precedence. I'm coming up with nothing that works. Anybody?

Best regards MC

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KAE 2021-8-20

The built in function orderfields might help.

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Answer 1

Stephen23 2021-5-20

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https://ww2.mathworks.cn/matlabcentral/answers/834988-sort-fields-of-struct-by-length-and-alphabetically#answer_704308

编辑：Stephen23 2021-5-20

在 MATLAB Online 中打开

S.aa = rand(3,1);
S.bb = 1;
S.cc = rand(8,2);
S.dd = 1;
S.Ee = 1;
S.Ff = rand(3,1)
S = struct with fields:
    aa: [3×1 double]
    bb: 1
    cc: [8×2 double]
    dd: 1
    Ee: 1
    Ff: [3×1 double]

Method one: sort and indexing:

N = structfun(@numel,S);
F = fieldnames(S);
[~,X] = sort(F);
[~,Y] = sort(N(X),'descend');
Z = orderfields(S,F(X(Y)))
Z = struct with fields:
    cc: [8×2 double]
    Ff: [3×1 double]
    aa: [3×1 double]
    Ee: 1
    bb: 1
    dd: 1

Method two: table and sortrows:

[~,X] = sortrows(table(N,F),[-1,2]);
Z = orderfields(S,F(X))
Z = struct with fields:
    cc: [8×2 double]
    Ff: [3×1 double]
    aa: [3×1 double]
    Ee: 1
    bb: 1
    dd: 1