Optimizing two vectors of different sizes

1 次查看(过去 30 天)
I am working to optimize the following problem:
r=optimvar('r',size(S,1),'LowerBound',0,'UpperBound',1);
B= optimvar ('B', size(dm,2));
p=prob2matrices({r, B},'Constraints', sum(r)<=1);
%Solving optimization problem
Roptimal=lsqlin([S', 1], dm(:), p.Aineq,p.bineq,[],[],p.lb,p.ub)
Where S is a n x m matrix, and dm is a m x 1 matrix. The result is that r (n x 1 natrix) and B (m x 1 matrix) are different sizes, and cannot be concatenated. The equation I am essential trying to solve is as follows:
%minimize "e2"
e= dm - (S'*r+B)
e2= e*e'
I recogonize I am probably not using an appropriate function. Any help would be greatly appreciated.
  2 个评论
Nagasai Bharat
Nagasai Bharat 2021-5-24
Hi,
From the equation (r' * S) would be a 1 x m matrix whereras B is a m x 1 matrix. Try to cross-check as a transpose of B would be needed to have an addition operation.
Adam Rish
Adam Rish 2021-5-24
编辑:Adam Rish 2021-5-24
So I adjusted my inputs, but am still getting the same error. Here is what I've written
r=optimvar('r',size(S,1),'LowerBound',0,'UpperBound',1);
p=prob2matrices({r},'Constraints', sum(r)<=1);
%Solving optimization problem
Roptimal=lsqlin([S', I], dm(:), p.Aineq,p.bineq,[],[],p.lb,p.ub)
So the equation I am trying to solve/minimize using lsqlin is the following:
S'*r+B-dm
Where I am trying to solve for r (n x 1 matrix) and B. S is still a n x m matrix, and dm is a 1 x m matrix. S'*r is therefore a m x 1 matrix. The problem is that I need B to be an m x 1 matrix but the requirement of multiplier I seems to prevent me from doing that

请先登录,再进行评论。

采纳的回答

Matt J
Matt J 2021-5-24
编辑:Matt J 2021-5-24
r=optimvar('r',n,'LowerBound',0,'UpperBound',1);
B= optimvar ('B', m);
[p,idx]=prob2matrices({r, B},'Constraints', sum(r)<=1);
C=nan(m,m+n);
C(:,idx.r)=S';
C(:,idx.B)=eye(m);
Roptimal=lsqlin(C, dm(:), p.Aineq,p.bineq,[],[],p.lb,p.ub);
sol=x2sol(Roptimal,idx), %solution

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Multiobjective Optimization 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by