Array indices must be positive integers or logical values.

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Carmela Marie Lingad
评论： Carmela Marie Lingad 2021-5-24
I uploaded my excel file and matlab code.
I want to portray the value of the elevation (El1). But to do this, what I need to do is, The value of Elevation in cell D5 should be the same value of elevation in cell L2. Then the value of the suceeding elevation should be calculated as, the value of the previous elevation minus the value of the difference of Db1 and Da1.
To further explain, the value of the elevation is 6m. Therefore, the elevation in cell D5 should be 6m as well. But the value of the elevation in cell D6 should be like this:
cell D6 = (cell D5 - 1) - (Db1 - Da1). And it should continue on until the last cell of elevation is computed. But of course, it should portray the negative value. So in cell D13, the elevation should be a negative number. I don't know how to portray the value.

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采纳的回答

Yutaka Yamada
Yutaka Yamada 2021-5-24
编辑：Yutaka Yamada 2021-5-24
It seems that Elev1 is the initial elevation.
I think it's better to get the array size first like below. Otherwise the array size of Db1 and El1 becoems different.
N = length(Db1);
El1 = zeros(N,1);
El1(1) = Elev1;
%elevation
for i = 1:N-1
El1(i+1) = El1(i) - (Db1(i+1) - Da1(i+1));
end
By running above script, you can get the below El1.
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Yutaka Yamada
Yutaka Yamada 2021-5-24
Could you try to copy and paste the above code again?
When I run the code, it becomes like below.

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更多回答（1 个）

KSSV
KSSV 2021-5-24
In MATLAB the indices of array should be strictly positive integers. Zeros and negative numbers are not allowed.
This loop in your code:
for i = 0:100
El1(i) = Elev1(i-1) - (Db1 - Da1);
end
when i = 0, Elev1(-1) and El1(0) are not valid. Thats why you got error. Change the loop index so that the index is positive.
  2 个评论
KSSV
KSSV 2021-5-24
编辑：KSSV 2021-5-24
If you put i = 1:100, Elev1(0) you will get and this will be an error. By the way Elev1 looks to be a constant? Not an array. And also Db1 and Da1 are arrays...the logic is not correct.

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