How to plot the graphs by fixing constants of your choice

Question

Ibrahim Bin Umair 2021-5-24

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/837913-how-to-plot-the-graphs-by-fixing-constants-of-your-choice

评论： Ibrahim Bin Umair 2021-5-24

I have this expression as output

C1*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) + C2*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2))*cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) - C3*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2))*sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2)

How can i plot the graph by fixing constants of my choice

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Answer 1

DGM 2021-5-24

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https://ww2.mathworks.cn/matlabcentral/answers/837913-how-to-plot-the-graphs-by-fixing-constants-of-your-choice#answer_707008

编辑：DGM 2021-5-24

在 MATLAB Online 中打开

C = [1 2 3] % pick some constants
x = linspace(0,50,100); % pick an interval
y = C(1)*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) ...
    + C(2)*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
    .*cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) ...
    - C(3)*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
    .*sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2);
plot(x,y)

or you could do the same thing using symbolic tools

syms x C1 C2 C3
y = C1*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) ...
    + C2*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
    *cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) ...
    - C3*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
    *sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2);
y = subs(y,[C1 C2 C3],[1 2 3]); % specify the constants
fplot(y,[0 50]) % specify the interval