unexpected use of 00:00:01 in a scalar context matlab

4 次查看(过去 30 天)
if abs(Int12{i,6}- F1{j,1}) <= '00:00:01' why is it not corret?
  1 个评论
Daniel Pollard
Daniel Pollard 2021-5-24
Can you give some more context? Since we don't know what Int12 or F1 are, it's not easy to help. What are you trying to do?

请先登录,再进行评论。

采纳的回答

Walter Roberson
Walter Roberson 2021-5-24
In MATLAB '00:00:01' is a character vector. When you use a character vector in a numeric expression, most of the time the character vector will have each character converted to the Unicode position number used to encode the character.
double('00:00:01')
ans = 1×8
48 48 58 48 48 58 48 49
You would then be comparing whatever is on the left side of the < to that vector of numbers, getting out a vector of logical results.
If the values you are working with just happen to be datetime objects then subtracting would give a duration object. You can then compare
if abs(Int12{i,6}- F1{j,1}) <= duration('00:00:01')
or more compactly
if abs(Int12{i,6}- F1{j,1}) <= seconds(1)

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Dates and Time 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by