Can someone help me? - Plotting complex number with index

I plotted complex numbers as follows:
and I got some complex numbers, like for example:
result plot:
how do I put the corresponding bit values (1000,1100, ...) according to the example below???
Can someone help me?

 采纳的回答

Hi,
Here is the answer to convert imaginary and real numbers from a floating point format into binary:
N = 16; % Number bits for integer part:
M = 25; % Number bits for fraction part:
% Conversion from floating point format into binary number
%% REAL Part:
for ii=1:numel(q_real)
BIN1(ii,:) = fix(rem(q_real(ii)*pow2(-(N-1):M),2));
% Test the inverse transformation
DEC1(ii) = BIN1(ii,:)*pow2(n-1:-1:-m).';
end
%% IMAG Part:
for ii=1:numel(q_imag)
BIN2(ii,:) = fix(rem(q_imag(ii)*pow2(-(N-1):M),2));
% Test the inverse transformation
DEC2(ii) = BIN2(ii,:)*pow2(n-1:-1:-m).';
end
Good luck.

更多回答(1 个)

4 个评论

Thanks for the tip!!!
I will try to reproduce!!
Could you explain the third step better?
L = 1e4; % number of bits
SNRdB = 0:28;
max_run = 100;
alpha = 0.3;
for sk = 1:length(SNRdB)
for tk = 1:max_run
% 1 ou -1 para sinal em fase (an)
x_inp_I = sign(rand(1,L)- 0.5);
% 1 ou -1 para sinal de quadratura (bn)
x_inp_Q = sign(rand(1,L)- 0.5);
% Gera bits de marca d'água aleatórios (dI)
Bit_wat_I = sign(rand(1,L)- 0.5);
% Gera bits de marca d'água aleatórios (dQ)
Bit_wat_Q = sign(rand(1,L)- 0.5);
for k = 1:L
if Bit_wat_I(k) == 1 && Bit_wat_Q(k) == 1
Bit_enviado(k) = (x_inp_I(k) .* ((sqrt(1-alpha)) + (sqrt(alpha)))) + (1i .* x_inp_Q(k) * ((sqrt(1-alpha)) + (sqrt(alpha))));
end
end
end
end
q_real = real(Bit_enviado);
q_imag = imag(Bit_enviado);

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