Creating a Matrix with a pattern

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James Wilson
James Wilson 2021-5-27
回答： Walter Roberson 2021-5-27
I am trying to create a pattern that starts to follow a pattern starting at the second row in the first column, then on the third row but starts on the second column and continues until an n term, creating a [n;n] matrix. The pattern is similar to this matrix:
A = [ 2,-2,0,0,0,0,0,0,0,0,0; -2,4,-2,0,0,0,0,0,0,0,0; 0,-2,4,-2,0,0,0,0,0,0,0; 0,0,-2,4,-2,0,0,0,0,0,0;
0,0,0,-2,4,-2,0,0,0,0,0; 0,0,0,0,-2,4,-2,0,0,0,0; 0,0,0,0,0,-2,4,-2,0,0,0; 0,0,0,0,0,0,-2,4,-2,0,0;
0,0,0,0,0,0,0,-2,4,-2,0; 0,0,0,0,0,0,0,0,-2,4,-2; 0,0,0,0,0,0,0,0,0,-2,4]
I am wondering how I can replicate the pattern above in a similar code then typing it out.
  1 个评论
Walter Roberson
Walter Roberson 2021-5-27
Ran in:
A = [ 2,-2,0,0,0,0,0,0,0,0,0; -2,4,-2,0,0,0,0,0,0,0,0; 0,-2,4,-2,0,0,0,0,0,0,0; 0,0,-2,4,-2,0,0,0,0,0,0;
0,0,0,-2,4,-2,0,0,0,0,0; 0,0,0,0,-2,4,-2,0,0,0,0; 0,0,0,0,0,-2,4,-2,0,0,0; 0,0,0,0,0,0,-2,4,-2,0,0;
0,0,0,0,0,0,0,-2,4,-2,0; 0,0,0,0,0,0,0,0,-2,4,-2; 0,0,0,0,0,0,0,0,0,-2,4]
A = 11×11
2 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2

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采纳的回答

Walter Roberson
Walter Roberson 2021-5-27
Ran in:
N = 11;
diag([2, 4*ones(1,N-2), 2]) + diag(-2*ones(1,N-1),1) + diag(-2*ones(1,N-1),-1)
ans = 11×11
2 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2 0 0 0 0 0 0 0 0 0 -2 4 -2

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