finding closest values in array
2 次查看(过去 30 天)
显示 更早的评论
Hello, want to locate a value from an pH array when closest to 4.756 and then locate the corresponding Vb value associated with that pH value. Any help would be appreciated. See last 2 lines.
format short
Kw = 1e-14;
Ka = 1.755388e-5;
pKa = 4.756;
%
Ca = 0.5;
Cb = 0.1;
Va = 100;
Vb = 0.05:0.05:2000;
Ma = (Ca * Va) / 1000;
Mb = (Cb .* Vb) ./ 1000;
for i = 1:length(Mb)
M_excess = Ma - Mb(i);
if abs(M_excess)<eps
Hplus = Ka * ((Ma_final * 0.999999) ./ Mb_final);
Vb_ev = Vb(i);
pH_ev = pH(end);
elseif M_excess > 0
Ma_final = (M_excess * 1000) ./ (Va + Vb(i));
Mb_final = (Mb(i) * 1000) ./ (Va + Vb(i));
Hplus = Ka * (Ma_final ./ Mb_final);
elseif M_excess < 0
OH = (M_excess * 1000 * (-1)) ./ (Va + Vb(i));
Hplus = Kw ./ OH;
end
pH(i) = -log10(Hplus);
end
%
pH_Mid_Pt2 = find pH value when closest to 4.756;
Vb_Mid_Pt2 = find corresponding Vb value at pH_Mid_Pt2;
0 个评论
采纳的回答
Richard Brown
2013-8-6
If I understand correctly, you want to find the pH value in your array closest to 4.756, and pull this value out, together with the corresponding Vb value. If that's right, this should do the trick.
[~, idx] = min(abs(pH - 4.756));
pH_Mid_Pt2 = pH(idx);
Vb_Mid_Pt2 = Vb(idx);
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!