changing range of calculations

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Salwa Ben Mbarek
Salwa Ben Mbarek 2021-5-28
评论： Walter Roberson 2021-5-29
Hello,
I've tried to change the following program until m=5 , n=5, p=5 rather than 4 . The error that I find while changing the matrix n or m is : Dimensions of arrays being concatenated are not consistent . Can you help me please? Thanks a lot.
function Frequencia_Table = Frequencia(v,lx,ly,lz)
% Building the array of values
m = [zeros(5,1); repelem([1:4]',6,1)];
n = [0; repmat(repelem([1 2 0]',2,1),4,1); 1; 1; 2; 2];
p = [repmat([1;0],14,1); 1];
Freq = [m, n, p, nan(size(m,1),1)];
v=3.*1e8;
% Function handle
f = @(lx,lz,ly) v/2.*sqrt((m./lx).^2 + (n./ly).^2 + (p./lz).^2);
%Calculate Frequencies (lx = 2, ly = 3, lz = 4) --> Enter the lengths here
lx=2;
ly=3;
lz=4;
Freq(:,4) = f(lx,lz,ly);
% Create a table of the results
Frequencia_Table = table(Freq(:,1),Freq(:,2),Freq(:,3),Freq(:,4),'VariableNames',{'m','n','p','Frequencia'});
end

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回答（1 个）

Walter Roberson
Walter Roberson 2021-5-29
function Frequencia_Table = Frequencia(v,lx,ly,lz)
% Building the array of values
maxval = 5;
m = [zeros(5,1); repelem([1:maxval]',6,1)];
n = repmat([0;0;1;1;2;2], maxval+1, 1);
n = n(2:end);
p = repmat([1;0],(maxval+1)*3,1);
p = p(2:end);
Freq = [m, n, p, nan(size(m,1),1)];
v=3.*1e8;
% Function handle
f = @(lx,lz,ly) v/2.*sqrt((m./lx).^2 + (n./ly).^2 + (p./lz).^2);
%Calculate Frequencies (lx = 2, ly = 3, lz = 4) --> Enter the lengths here
lx=2;
ly=3;
lz=4;
Freq(:,4) = f(lx,lz,ly);
% Create a table of the results
Frequencia_Table = table(Freq(:,1),Freq(:,2),Freq(:,3),Freq(:,4),'VariableNames',{'m','n','p','Frequencia'});
end
  2 个评论
Salwa Ben Mbarek
Salwa Ben Mbarek 2021-5-29
Thank you very much Walter .
In fact, when I ran this second program, I don't find all combinaisons . The idea is I want all combinaisons of n,m,p changing from 0 to 5 (n=5, p=1, m=5, n=4, p=0, m=5, ....) ..Could you help me to do that?
Thanks
Walter Roberson
Walter Roberson 2021-5-29
Ran in:
[N, M, P] = ndgrid(0:5);
combinations = [N(:), M(:), P(:)]
combinations = 216×3
0 0 0 1 0 0 2 0 0 3 0 0 4 0 0 5 0 0 0 1 0 1 1 0 2 1 0 3 1 0

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