How to load MAt file into 3D matrix

8 次查看(过去 30 天)
I want to load 516 Mat files(240x320)into a 3D Matrix A(240,320,516)
The files are called PVCWARM00071,....,PVCWARM0007516
my code so far:
A = zeros(240,320,516)
nummer=0
>> for i= 1:516
nummer = nummer +1
ext = '.MAT'
naam = 'PVCWARM0007'
file= strcat(naam,num2str(nummer),ext)
A(:,:,i) = load(file)
end
i get the error:Conversion to double from struct is not possible. i already tried to make some adjustments with struct2cell and cell2mat without result.
Can someone help?
Thanks
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2013-8-9
What is the name of your matrix in you mat file?
Maxim De Roeck
Maxim De Roeck 2013-8-9
the 3d matrix is called A, the Mat files are 240x320 arrays without a name

请先登录,再进行评论。

采纳的回答

Evan
Evan 2013-8-9
编辑:Evan 2013-8-9
The answer can be found in the documentation of the load function:
S = load(FILENAME) loads the variables from a MAT-file into a structure array, or data from an ASCII file into a double-precision array.
Since you already initialize A as a double, the line A(:,:i) = load(file) is attempting to save load's structure output into your 3D matrix.
If you already know the name of your variables as they are saved in your mat file, you can call load without an output argument to put them in the workspace, then save them to your 3D matrix. Again, though, it helps to know or find out the variable names when doing this:
A = zeros(240,320,516);
nummer = 0;
for i = 1:516
nummer = nummer +1
ext = '.MAT';
naam = 'PVCWARM0007';
file = strcat(naam,num2str(nummer),ext);
load(file)
A(:,:,i) = B; %if, for example, the variable's name is B
end
  7 个评论
Maxim De Roeck
Maxim De Roeck 2013-8-9
i fixed it:
for i = 1:516
eval(['load PVCWARM0007',int2str(i),';']);
eval (['A(:,:,i) = PVCWARM0007',int2str(i),';']);
end
thanks anyway!!
Evan
Evan 2013-8-9
编辑:Evan 2013-8-9
The method you're using is not recommended, which is why I suggested using dynamic field references. See Azzi's link for an explanation of why eval should be avoided. You also might find this page helpful.

请先登录,再进行评论。

更多回答(1 个)

Azzi Abdelmalek
Azzi Abdelmalek 2013-8-9
编辑:Azzi Abdelmalek 2013-8-9
A = zeros(240,320,516)
nummer=0
for i= 1:516
nummer = nummer +1
ext = '.MAT'
naam = 'PVCWARM0007'
file= strcat(naam,num2str(nummer),ext)
variable_name=whos('-file',file);
x=load(file)
A(:,:,i) = x.(variable_name.name)
end
  2 个评论
Maxim De Roeck
Maxim De Roeck 2013-8-9
编辑:Azzi Abdelmalek 2013-8-9
i fixed it:
for i = 1:516
eval(['load PVCWARM0007',int2str(i),';']);
eval (['A(:,:,i) = PVCWARM0007',int2str(i),';']);
end
thanks anyway!!

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by