How to perform a calculation only when a input value is positive

9 次查看（过去 30 天）
Kevin Burg
Kevin Burg 2021-5-31
评论： Kevin Burg 2021-5-31
I have a input file that has 1x367 inputs. I only want to calculate the following equation when the input value is positive. I thought this would be done through a for loop but that appears to not not be valid. How can I perform this calculation such that only a positive value is used? I thought a for loop would be the correct choice and also tried an if statement. Is there a better way to do this?
for chi_e > 0.0
j_l = ((1-chi_e)*m_dot)/(rho_L*((pi*D^2)/4));
end

请先登录，再回答此问题。

采纳的回答

Abhinav Gupta
Abhinav Gupta 2021-5-31
编辑：Abhinav Gupta 2021-5-31
Let your input variable be a of size = 1x367
Let b be the variable which consist of all positive elements of a.
b = a( a>= 0 );
for i = 1:1:length(b)
j_l = ((1-b(i))*m_dot)/(rho_L*((pi*D^2)/4));
disp(j_l);
end
Or simply,
b = a( a>= 0 );
j_l = ((1-b)*m_dot)/(rho_L*((pi*D^2)/4));

更多回答（1 个）

Scott MacKenzie
Scott MacKenzie 2021-5-31
It is not clear what you mean by "input value", but assuming you do know, then...
for chi_e > 0.0
if input_value > 0
j_l = ((1-chi_e)*m_dot)/(rho_L*((pi*D^2)/4));
end
end
  1 个评论
Kevin Burg
Kevin Burg 2021-5-31
Sorry, I have a pre-calculated matrix of positive and negative values for chi_e. I only want to use positive values of chi_e in the j_l formula.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品


版本

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by