Error : Subscripted assignment dimension mismatch.

Chao Zhang

2021 5 31

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When I ran the following code to the line 'M_ORE(i,:) = table2array(M_ROCK(i,:));', the error 'subscripted assignment dimension mismatch' appeared.

This is the screenshot of part dataset, I want to transfer values from M_ROCK into M_ORE1 and M_ORE2 according to the 'r1_mill_tonnage' and 'r2_mill_tonnage' strings.

Therefore, how to slove the error 'sunscripted assignment dimension mismatch' and get the correct objective matrix?

Many thanks in advance for your help!

elseif rock_index == 2
%%  
    M_ROCK = rock;
    M_ROCK = array2table(M_ROCK,'VariableNames',G_Value.Properties.VariableNames);
%
num=input('Please enter the number of rock types:');
%
M_WASTE = zeros(R1,C1);
M_ORE = zeros(R1,C1,num);
STR = cell(1,num);
    
for i = 1 : R1
         
         for j = 1 : num
             
             STR{j} = sprintf('r%d_mill_tonnage',j);
         
         if table2array(M_ROCK(i,STR{j})) > 0
             
             M_ORE(i,:) = table2array(M_ROCK(i,:));
        
         else
             
             M_WASTE(i,:) = table2array(M_ROCK(i,:));
         
         end
         
         end
         
end

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Walter Roberson 2021-6-1

No it is not, not in the posted code.

Walter Roberson 2021-6-2

I would claim that R1 is not a current row index into M_ROCK, and is instead exactly 814723 .

You could disprove this claim by posting the code that sets R1 and by showing the size() of M_ROCK and the value of R1 at the time that the error occurs.

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