Is there a more efficient way to compute this other than using a loop ?

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Rayan Glus
Rayan Glus 2021-5-31
评论： Rayan Glus 2021-5-31
Hello,
Say, vectors a and b have different sizes. I wonder if there is a simpler and more efficient way of writing the lines below.
b = [1 3 4 7 8 10 2 5 6];
a = [2 3 9];
for ii = 1:length(a)
b(b==a(ii))=[];
end
Output:
b = 1 4 7 8 10 5 6
Thanks!

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采纳的回答

Matt J
Matt J 2021-5-31
编辑：Matt J 2021-5-31
b=setdiff(b,a,'stable')

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