Solving composite equations with symbolic toolbox
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Hi all,
I have a very simple code written to solve for two variables within two equations. My main variables are A and B, which are renamed to AR and BR later in the program. My constants are w, g, alphaL, and p. The initial equation is quadratic and thus will have two answers. I want each of these answers to be plugged into a new equation, a cubic equation, to therefore produce 6 differing solutions. I am not sure how to do this via symbolic toolbox, so any help would be seriously appreciated. Thanks!
syms A B w g alphaL p % w = (mu - V0)
eqn = B*(A + B)*(2*w - g*(A + 2*B)) - alphaL^2 == 0;
AR = solve(eqn,A);
neqn = -4*(B - p)*(AR + B - p)*(2*w - g*(AR + 2*B + p)) == 0;
BR = solve(neqn,B);
3 个评论
John D'Errico
2021-6-1
You CAN do it that way, at least, in this case, you can. However, the symbolic toolbox is better used to solve the two equations simultaneously. It has no problem with understanding there should be 6 solutions. @Sulaymon Eshkabilov shows how to do that.
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Sulaymon Eshkabilov
2021-6-1
Hi,
Here is the corrected code with the symbolic solutions (A, B) of the two equations:
clearvars
syms A B w g alphaL p AR
eqn1 = B*(A + B)*(2*w - g*(A + 2*B)) - alphaL^2 == 0;
eqn2 = -4*(B - p)*(AR + B - p)*(2*w - g*(AR + 2*B + p)) == 0;
SOL = solve(eqn1, eqn2,A, B);
A_solution=SOL.A;
B_solution=SOL.B;
Good luck.
2 个评论
Sulaymon Eshkabilov
2021-6-2
Most welcome!
The last two lines are separation of solutions of A and B variables.
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