How to find position of a new point along a series of line segments?
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Say that you know that your query point Q is colinear to one line segment in a sequence of line segments XY. If XY is an Mx2 array and you wanted to insert your 1x2 point Q into XY, how do you figure out which two points of XY to split up? Example"
XY = [1 1; 2 1; 3 1; 5 1; 9 1];
Q = [7 1];
% Figure out where Q lies within XY
% indQ = ...
newXY = vertcat( XY( 1:indQ, : ), Q, XY( indQ+1 : end, : ) );
Sure you could test colinearity of Q to each line segment of XY. I'm wondering if there is a geometric construct for this, though.
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采纳的回答
Adam Danz
2021-6-1
编辑:Adam Danz
2021-6-1
XY = [1 1; 2 1; 3 1; 5 1; 9 1];
Q = [7 1];
XYQ = sortrows([XY;Q])
For coordinates along a non-linear line, you can compute the distance between Q (1xn) and each point in XY (mxn). Q is inserted between the two points in XY that are the shortest distance to Q if and only if the two points are next to each other. If the two closest points are not next to each other then placement of Q cannot be determined and an error will be thrown by the assert command.
XY = [1 1; 2 1; 3 1; 5 1; 9 1];
Q = [7 1];
dist = pdist2(Q,XY);
[~, min2idx] = mink(dist,2);
assert(diff(min2idx)==1, 'Placement cannot be determined.')
XYQ = [XY(1:min2idx(1),:); Q; XY(min2idx(2):end,:)]
Demo using non-linear coordinates
x = 0:.5:pi;
XY = [x',sin(x)'];
Q = XY(5,:)
XY(5,:) = []
dist = pdist2(Q,XY);
[~, min2idx] = mink(dist,2);
assert(diff(min2idx)==1, 'Placement cannot be determined.')
XYQ = [XY(1:min2idx(1),:); Q; XY(min2idx(2):end,:)]
plot(XYQ(:,1), XYQ(:,2), 'bo-')
hold on; grid on
plot(Q(1),Q(2),'r*')
The first method, using sortrows, works for all of these examples but would fail in some non-linear lines such as circles.
3 个评论
Adam Danz
2021-6-1
Collinearity implies straight lines,
I'll update my answer to show how to sort nonlinear coordinates.
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