In Quiver Function Error: " index must be a positive integer or logical."

1 次查看(过去 30 天)
Hey,
I get the error
??? Attempted to access quiver(2.76604,2.17365,-0.123257,0.81116); index must be a positive integer or logical.
and can't imagine why, because if I type quiver(2.76604,2.17365,-0.123257,0.81116) in the Command Window it works well.
Here is the Code:
for k=1:n
for l=1:n
if E(k,l) >= 1
x1=2+cos(2*pi/n*k); x2=2+cos(2*pi/n*l); y1=2+sin(2*pi/n*k); y2=2+sin(2*pi/n*l);
u=y1-x1; v=y2-x2;
quiver(x1,x2,u,v);%,'Color',color,'LineWidth',2);
end
end
end
with n=length(E) and E(i,j) = 1 if there excists an arrow between i and j
Thank You Daniel
  3 个评论
Daniel
Daniel 2013-8-13
Hmm this is weird because if I run exactly your modification of the code I get the error:
??? Attempted to access quiver(1.5,1.5,1.36603,1.36603); index must be a positive integer or logical.
Error in paintgraph at 23
quiver(x1,x2,u,v);
I can't imagine why. Yes the code I presented yields the error.

请先登录,再进行评论。

采纳的回答

Sajid Khan
Sajid Khan 2013-8-13
use clear all before executing your code.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Vector Fields 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by