Using ndgrid in arbitrary dimensions

Question

melampyge 2013-8-13

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Hi,

I have a 3x20 matrix called b. If I use ndgrid like this:

[xx, xy, xz] = ndgrid(b(1,:),b(2,:),b(3,:));

I get 20x20x20 matrices for each parameter xx,xy and xz which is what I want in the case that b has 3 rows. My problem is, I need to generalize this, for example, b might be 4x20 matrix or 5x20 matrix. In these cases I need to write the code like this:

[xx, xy, xz, xa] = ndgrid(b(1,:),b(2,:),b(3,:),b(4,:));

So my question is, how do I generalize this to an arbitrary M dimension, that is, if I have b as a Mx20 matrix, how can I use ndgrid?

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Answer 1

Sean de Wolski 2013-8-13

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https://ww2.mathworks.cn/matlabcentral/answers/84642-using-ndgrid-in-arbitrary-dimensions#answer_94205

编辑：Sean de Wolski 2013-8-13

在 MATLAB Online 中打开

There's a fun exercise in crashing my computer. Don't use a large b ;)

b = magic(3); %example
bc = num2cell(b,1); %cells columnwise
clear bbc; %in case it exists
[bbc{1:numel(bc)}] = ndgrid(bc{:}); %use comma-separated list expansion on both sides

comma separated lists

Note, instead of creating four new variables, I create a cell array that contains them. This scales much better!

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melampyge 2013-8-13

Actually I want to do it this way. I made my matrix b smaller (after several Matlab and computer crashes) and after that I got an array bcc with 1x15 cells, now I need to create xx, xy, xz 15x15x15 matrices from these cells I guess.

melampyge 2013-8-13