Array concatenation in for loop

Question

0 个投票

Hi,

I am doing some operation with for loop. The result of each iteration, let's say F1 needs to be svaed in the big matrix G as shown below.

for i = 1:1:10
G (:,:,i) = F1
end

However, the size of the matrix F1 varies for each iteration, owing to this I am getting the following error, Any idea how to handle this

Unable to perform assignment because the size of the left side is 1-by-1444 and the size of the right side is 1-by-1225.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

Answer 1

KSSV 2021-6-3

编辑：KSSV 2021-6-3

0 个投票

When the size of matrix varies, the option to save the matrix is a cell array.

G = cell(10,1) ; 
for i = 1:1:10
G{i} = F1 ;
end

Later you can access the matrices using cell indexing. G{1}, G{2},....G{10}

KSSV 2021-6-3

Thanks is accepting/ voting the answer. :)

Big Data 2021-6-3

Sorry.. Forgot to do.. Done now..

Cheers !!!!