Im not a 100% sure if this is what you are asking for, but as for checking for multiple maximums you are actually already doing this.
Example:
%here test(:,2) has two max values.
test=[1,2;...
2,3;...
3,3];
indx=test(:,2)==max(test(:,2))
indx =
0
1
1
index now holds true if test(:,2) is the maximum value. if there are more then 1 true element in indx , it means that there are several maxima so to test for this simply use :
if nnz(indx)>1
to check for the maximum x value (i assume this is test(:,1) ) you do the same exercise but use logical indexing to sort out the possible candidates:
indxX=test(:,1)==max(test(indx,1));%i assume that x values cannot be equal
indxX now holds the index for the row containing maximum value of both x and y.
so Qevents(i)=test(indxX,2);
Another more readable solution would be to use sort and find.
test=[1,2;...
3,3;...
2,3]; % i now made sure that the x values are not sorted.
% sort the array with respect to x values.
[~,idx]=sort(test(:,1));
test=test(idx,1:2); % remember to also switch around the y values.
Then you can use find(..) to get the last maximum y value (since x is now sorted)
indx=find(test(:,2)==max(test(:,2)),1,'last');
Note that index is now a scalar index and not a logical vector. But still the value you are looking for is:
test(indx,2);
Play around with the two methods see which one fits you best =)
