When I executed below code it got executed perfectly but in the graph I am getting just the coordinates but not the plot.

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keerthana reddy 2021-6-4

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评论： keerthana reddy 2021-6-9

f=10; %frequency of the impulse in Hz
fs=f*100; % sample frequency is 10 times higher
t=-1:1/fs:1; % time vector
x= 100*cos(2*pi*1000*t);
y=zeros(size(t));
y(1:fs/f:end)=1; 
for t= -1:1/fs:1
    m = x.*y;    
end
plot(t,m);

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Walter Roberson 2021-6-7

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f=10; %frequency of the impulse in Hz
fs=f*100; % sample frequency is 10 times higher
t=-1:1/fs:1; % time vector
numt = length(t);
y=zeros(size(t));
y(1:fs/f:end)=1; 
for tidx = 1 : numt
  x = 100*cos(2*pi*1000*t(tidx));
  m(tidx, :) = x.*y;    
end
plot(t,m);

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Walter Roberson 2021-6-7

在 MATLAB Online 中打开

f = 10; %frequency of the impulse in Hz

fs = f * 7; % sample frequency is 7 times higher

t =-1/10:1/fs:1/10; % time vector

y = 100*cos(2*pi*1000*t);

stem(t, y)

Notice that we reduced the sampling frequency and the time interval.

Notice too that no loop was needed.

keerthana reddy 2021-6-9

Wow!! This is great.Thank you for helping.

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Srivardhan Gadila 2021-6-7

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Based on the above code it is clear that there is no use of the for loop by redefining the variable t to iterate over the loop and the value of m = x.*y; will be same for all the iterations. I think what you are looking for is may be the following:

f=10; %frequency of the impulse in Hz
fs=f*100; % sample frequency is 10 times higher
t=-1:1/fs:1; % time vector
x= 100*cos(2*pi*1000*t);
y=zeros(size(t));
y(1:fs/f:end)=1; 
% Removing the for loop
m = x.*y;
plot(t,m);

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keerthana reddy 2021-6-7

Yeah, I just checked putting breakpoints. But, can you tell me how can I get different x at different t. But y value should be constant and when I execute m = x.*y I need to get discrete values.

Srivardhan Gadila 2021-6-7

编辑：Srivardhan Gadila 2021-6-7

If your equation is m(tidx) = x(tidx) * y(tidx) then the above code in my answer should work fine because with the operator times, .* element wise multiplication is performed so you don't have to iterate over individual elements of the vectors x and y, refer to the documentation of times, .* for more information. If your equation is m(tidx) = x(tidx) * y then you can refer to the below code posted by Walter.

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