How to process a matrix

2 次查看(过去 30 天)
Sharen H
Sharen H 2013-8-16
clc
clear all
BW=[ 0 0 0 0 1 0 0 0 0 1 0 0 0
0 0 0 0 1 0 0 0 0 1 0 0 0
0 0 0 0 1 0 0 0 0 1 0 0 0
1 0 0 0 1 0 0 0 0 1 0 0 0]
[m,n]=size(BW)
x=1;
y=1;
count=0;
edgedet=edge(BW,'log');
for i=1:m
for j=1:n-1
if(edgedet(i,j)~=edgedet(i,j+1))
c(x)= i;
x= x+1;
d(y)=j;
y=y+1;
break;
count=count+1;
end
end
end
plot(c,d)
is it possible to do the search from the other side of the matrix as we do in C programming
for i=m:1
for j=n:2
if(edgedet(i,j)~=edgedet(i,j-1))
c(x)= i;
x= x+1;
d(y)=j;
y=y+1;
break;
count=count+1;
end
end
end

采纳的回答

Matt J
Matt J 2013-8-16
Yes, you can loop backward by doing
for i=m:-1:1
etc...

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by