Appending vectors in a loop

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T 2013-8-17

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https://ww2.mathworks.cn/matlabcentral/answers/84959-appending-vectors-in-a-loop

Data2= Columns 1 through 2

    [ 4]    [0.0119]   
    [ 5]    [0.0119]   
    [ 6]    [0.0143]   
    [ 7]    [0.0143]
    [ 8]    [0.0187]   
    [ 9]    [0.0256]   
    [10]    [0.0273]   
    [11]    [0.0119]   
    [12]    [0.0143]

I want to be able to take in values from data2 for column 2 using the corresponding values in column 1 and data1 . I would use the following command:

find(ismember(cell2mat(data2),data1)==1);

The problem, if you look closely at the first set, is that there is a -1. I need to force it’s value to be zero. Thus I would have to append the vector.

If the command about is within a loop, how do I append data2 without prompting an error?

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Azzi Abdelmalek 2013-8-17

What are you expecting as result, you can make your example shorter

T 2013-8-18

编辑：T 2013-8-18

在 MATLAB Online 中打开

I am expecting:

Data2=

[ 4]    [0.0119]   
  [ 5]    [0.0119]   
  [ 6]    [0.0143]   
  [ 7]    [0.0143]
  [ 8]    [0.0187]   
  [ 9]    [0.0256]   
  [10]    [0.0273]   
  [11]    [0.0119]   
  [12]    [0.0143]  
  [-1]    [ 0 ]

and I want to be able to retrieve the second column in Data1 with each corresponding value in column 1 of Data2.

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采纳的回答

Azzi Abdelmalek 2013-8-17

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https://ww2.mathworks.cn/matlabcentral/answers/84959-appending-vectors-in-a-loop#answer_94480

编辑：Azzi Abdelmalek 2013-8-17

在 MATLAB Online 中打开

out=Data2(ismember(cell2mat(Data2(:,1)),Data1),:)

% to change values of Data1 from -1 to 0

Data1(Data1==-1)=0

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Azzi Abdelmalek 2013-8-19

在 MATLAB Online 中打开

find(ismember([a{:}],[Data1{:}]))

T 2013-8-19

编辑：T 2013-8-19

find(ismember([a{:}],[Data1{:}])==1) is what I needed, thanks.

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更多回答（1 个）

Andrei Bobrov 2013-8-18

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https://ww2.mathworks.cn/matlabcentral/answers/84959-appending-vectors-in-a-loop#answer_94541

编辑：Andrei Bobrov 2013-8-18

在 MATLAB Online 中打开

Data2 =  [...
          4       0.0119
          5       0.0119
          6       0.0143
          7       0.0143
          8       0.0187
          9       0.0256
         10       0.0273
         11       0.0119
         12       0.0143]
out = Data1*[1 0];
[l,ii] = ismember(Data1,Data2(:,1));
out(l,2) = Data2(ii(l),2);