min function on two arrays
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I've read the documentation on the min function, but still don't understand how it works on two arrays. I have the following:
dS=zeros(1,N)
dS=min(cA(i+1,:),cB(i+1,:))
where cA and cB are equally sized arrays. Doesn't the min function just take the value at equivalent locations in cA or cB that is the lowest. So if position 10,50 in cA is 5 and the same position in cB is 3, min returns 3 in the resulting row vector, dS, at column 50. Is that correct?
3 个评论
James Tursa
2021-6-8
Yes. Are you getting a result you don't expect?
Robert Demyanovich
2021-6-8
James Tursa
2021-6-8
编辑：James Tursa
2021-6-8
This line creates dS as a vector:
dS=zeros(1,N)
Then this line completely overwrites the dS you just created and instead assigns dS the result of the min( ) function call:
dS=min(cA(i+1,:),cB(i+1,:))
I.e., the first line is completely useless and accomplishes nothing because it gets overwritten in the second line.
And yes, cA(i:1,:) and cB(i+1,:) will be a row vectors if i is a scalar.
采纳的回答
SALAH ALRABEEI
2021-6-8
%
dS=min([cA(i+1,:),cB(i+1,:)])
3 个评论
Walter Roberson
2021-6-8
The above would take the single overall minimum of the two rows i+1 of cA and i+1 of cB . cA(i+1,:) is a row and so is cB(i+1,:), and [] of two rows creates a combined row, so the min() is going to be applied to a vector; it would take the minimum of that resulting vector.
SALAH ALRABEEI
2021-6-8
Oops, yes it must be semicol; Thanks.
% correction
dS=min([cA(i+1,:);cB(i+1,:)])
Walter Roberson
2021-6-8
That would work in the case that cA and cB have the same number of columns.
The original code
dS=min(cA(i+1,:),cB(i+1,:))
would also work if one of cA or cB had a single column and the other one did not.
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