Feature vector dimension reduction (PCA)

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Andrea Daou
Andrea Daou 2021-6-9
评论： Andrea Daou 2021-6-11
Hello,
How can reduce a feature vector of dimension K*N to a feature vectore of dimension K*M with M<N (image classification task)?
I read about PCA but I am not understanding how can I use it to get the K*M vector.
Appreciate your help!
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Andrea Daou
Andrea Daou 2021-6-9
编辑：Andrea Daou 2021-6-9
I read about [coeff, score] = pca(features) but for example if I have a dimesion equal to 1340*5435 and I want to pass to 1340*M, is new_features = score(:,1:M) a good solution ?
This solution has a limitation: M cannot take a value > 1340
Thank you in advance,
J. Alex Lee
J. Alex Lee 2021-6-9
I'm not sure what is returned by pca(), but presumably coeff is KxN (the rotated coefficents)? Then is your question how to decide M? Is score a vector 1xN?

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the cyclist
the cyclist 2021-6-9
I have written an answer to this question that explains in detail how to use MATLAB's pca function, including how to do dimensional reduction. I suggest that you read that question, answer, comments from other users, and my responses. I expect this will answer your question.
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the cyclist
the cyclist 2021-6-11
Use the coeff matrix from the PCA you did previously, to transform the 1xN vector in the original space into a 1xN vector in the PC space, then use the first M columns. That 1xM vector is the feature-reduced vector in the new space.

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