How to replace an element in an struct array

2013 8 21
1 个回答
回答已采纳
6 次查看（30 天）

0 个投票

Hi,
I have a problem about replacing an element in the array with a new one.
Could you please take a look and tell me what i'm doing wrong?
breedpop =
1x100 struct array with fields:
sched
harvvol
npv
penalty
fitness
% every array has 10 element in it.
I tried to replace one of the element in the breedpop.penalty array(doesnt matter index of the element) this way
breedpop(i).penalty = newgeneration(i).penalty;
It works if i run once but when i run it more than 100(number of iteration) bredpop.penalty becomes more than 10 element.
How can I do it?

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Walter Roberson
Walter Roberson 2013-8-21
We would need to see more about how you create newgeneration(i).penalty

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-8-21
编辑：Azzi Abdelmalek 2013-8-21

0 个投票

Because newgeneration(i).penalty when i >100 contains more then 10 elements
If you want to take the first 10 elements
breedpop(i).penalty(1:10) = newgeneration(i).penalty(1:10);

2 个评论
显示 无 隐藏 无

tevzia
tevzia 2013-8-21
I wanna replace one from the list(newpopulation.penalty) to old list (breedpop.penalty)
breedpop(i).penalty = newgeneration(i).penalty(end)
however it didn't work
tevzia
tevzia 2013-8-21
I solve it. thank you
breedpop(n).penalty = newpopulation(i).penalty(end)
n is the last one of the list (number of the elements)

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Structures 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by