finding principal axis and moments of inertia tensor using eig function

25 次查看(过去 30 天)
Good Morning,
I am trying to calculate the principal moment of inertia as well as the principal axis of inertia.
If I am given a tensor matrix of the rotational moment of inertia:
I=[Jx -Jxy -Jxz; -Jxy Jy -Jyz; -Jxz -Jyz Jz];
And wish to find the principal moments and principal axis of inertia then I would simply use matlab eig.
[Axes,Moments]=eig(I);
And then diagonal of the Moments matrix is the principal moments. Now say I want to find the cosine of the angle of the principal axis of inertia with the three axes X,Y,Z that are center at the CG...how would I go about this?
Is it cos(Axes(:,1)), cos(Axes(:,2)), cos(Axes(:,3)??
Thank you.

采纳的回答

Roger Stafford
Roger Stafford 2013-8-27
"Is it cos(Axes(:,1)), cos(Axes(:,2)), cos(Axes(:,3)??"
No, the components of the eigenvectors themselves, Axes(:,1)), Axes(:,2), Axes(:,3), are already the cosines of the angles between the three principal axes of inertia respectively and the x, y, and z axes, provided the eigenvectors are normalized.
Of course there is an ambiguity about the sense of each of these vectors depending on which of two opposite directions are to be considered as the positive directions of these axes of inertia.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Physics 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by