Calculating Contribution by group

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Pete sherer 2021-6-16

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https://ww2.mathworks.cn/matlabcentral/answers/857715-calculating-contribution-by-group

评论： Scott MacKenzie 2021-7-29

Hi,

I am trying to calculate the contribution within a group. Currnetly I am using below procedure, looking for ways to do it faster/ shorter format

tdata= table([2220;2220;2220;2768;3032;3032;3797;3797;3797;3797],["UNITED KINGDOM";"UNITED KINGDOM";"UNITED KINGDOM";"UNITED KINGDOM";"GERMANY";"UNITED KINGDOM";"UNITED KINGDOM";"UNITED KINGDOM";"UNITED KINGDOM";"UNITED KINGDOM"],["GBR_SW";"GBR_B";"GBR_B";"GBR_WC";"DEU_60";"GBR_SW";"GBR_WC";"GBR_GU";"GBR_NW";"GBR_WC"],[76449.0759200000;12117334.4450944;12197494.6611334;0;29611.6627483313;6501105.79043613;27555.3049246048;65116.2649056192;65568.0789443064;126369.558005001],'VariableNames',{'EB','Country','CRESTACode','Limit'})
% Aggregating by group of EB-Country-Cresta
[ uniqEBCntry_2Cresta, ~, JGrp]      = unique( tdata( :, {'EB','Country','CRESTACode'}));
uniqEBCntry_2Cresta.count            = accumarray( JGrp, 1, [], @sum);
uniqEBCntry_2Cresta.Limit = accumarray( JGrp, tdata.Limit, [], @sum);
% Summing across all cresta
[ uniqEBCntry, ~, JGrp] = unique( uniqEBCntry_2Cresta( :, {'EB','Country'}));
uniqEBCntry.Limit_byEBCntry = accumarray( JGrp, uniqEBCntry_2Cresta.Limit, [], @sum);
%Contribution by CRESTA for each EB-Country
uniqEBCntry_2Cresta = innerjoin( uniqEBCntry_2Cresta,  uniqEBCntry, 'Keys',{'EB','Country'},'RightVariables',{'Limit_byEBCntry'});
uniqEBCntry_2Cresta.contrib = uniqEBCntry_2Cresta.Limit./ uniqEBCntry_2Cresta.Limit_byEBCntry;

Thanks

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Pete sherer 2021-6-20

any suggestion?

Scott MacKenzie 2021-7-29

It's nice that you have posted code, but, in this case, it might also help if you clearly define "contribution within a group" and give an example with the data in your table.

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