How to convert arc circle plot into binary circle?
显示 更早的评论
采纳的回答
R = 1;
th = linspace(0,2*pi,1000) ;
x = R*cos(th) ; y = R*sin(th) ;
xi = linspace(-2,2,100) ;
yi = linspace(-2,2,100) ;
[X,Y] = meshgrid(xi,yi) ;
Z = zeros(100) ;
idx = knnsearch([X(:) Y(:)],[x' y']) ;
Z(idx) = 1 ;
imagesc(Z)
3 个评论
afiq rauf
2021-6-17
KSSV
2021-6-17
Remove the arc?
Walter Roberson
2021-6-19
Change
th = linspace(0,2*pi,1000) ;
to only have the range of angles that you want the arc to cover.
更多回答（1 个）
https://matlab.fandom.com/wiki/FAQ#How_do_I_create_an_arc.3F shows how to create an arc.
But for your purpose, instead of using plot(), multiply the coordinates by the resolution you want, and round() them, and then subtract off the minimum x and y . Now you have matrix coordinates.
resolution = 25;
th = linspace(0, 7*pi/9, 500);
r = 5;
xc = 3;
yc = 7;
[x,y] = pol2cart(th, r);
x = x + xc;
y = y + yc;
%the above are data coordinates. Make them into array coordinates.
buffer = 5;
xm = round(x * resolution);
ym = round(y * resolution);
xmin = min(xm);
ymin = min(ym);
xmax = max(xm);
ymax = max(ym);
xmc = xm - xmin + 1 + buffer;
ymc = ym - ymin + 1 + buffer;
arc_image = accumarray([ymc(:), xmc(:)], 1);
imshow(arc_image)
类别
在 帮助中心 和 File Exchange 中查找有关 Axes Transformations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
