Eliminate string from vector
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Hi, i created a vector containing 963 nc file. The problem is that some of them are the same but from two different version and i want to delete the previous version. For example, how can i eliminate row 844, 846 and 848 from my vector? Thanks all
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Image Analyst
2021-6-19
You say "For example from c_gls to S1CSAR" so basically up until the last underline. Don't include _V and anything after that. This will do it:
% Create sample data
ca = {...
'c_gls_SSM1km_202007310000_CEURO_S1CSAR_V1.1.1.NC';...
'c_gls_SSM1km_202007310000_CEURO_S1CSAR_V1.1.2.NC';...
'c_gls_SSM1km_202008040000_CEURO_S1CSAR_V1.1.1.NC';...
'c_gls_SSM1km_202008040000_CEURO_S1CSAR_V1.1.2.NC';...
'c_gls_SSM1km_202008050000_CEURO_S1CSAR_V1.1.1.NC';...
'c_gls_SSM1km_202008050000_CEURO_S1CSAR_V1.1.2.NC'}
% Loop over each cell replacing it with the contents
% but only until the last underline.
for k = 1 : length(ca)
underlineIndexes = find(ca{k} == '_');
% Take up until the last underline
ca{k} = ca{k}(1:underlineIndexes(end) - 1);
end
ca = unique(ca) % Get unique and show results in command window.
You get
ca =
3×1 cell array
{'c_gls_SSM1km_202007310000_CEURO_S1CSAR'}
{'c_gls_SSM1km_202008040000_CEURO_S1CSAR'}
{'c_gls_SSM1km_202008050000_CEURO_S1CSAR'}
Is that what you want?
If you know that the last underline is always in the same location, you could simplify it to be
for k = 1 : length(ca)
ca{k} = ca{k}(1:38); % Extract the first 38 characters of the kth cell.
end
OK, 3 lines instead of 1 for the regexp() way, but you might find this more intuitive and less cryptic.
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Image Analyst
2021-6-18
Did you try the unique() function? It has lots of options so be sure you understand which options to use.
If you need more help, attach your cell array in a .mat file with the paperclip icon.
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