circle through 3 points equation

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Ahmad Alhaj Jnaid
Ahmad Alhaj Jnaid 2021-6-20
编辑： Matt J 2021-6-20
Hi, i have an exercise for the university.
Through three points A, B, C ∈ R2 that do not lie on a straight line can be exactly one circle lay. Circle center M and radius r can be calculated using a linear 3 × 3 system of equations u1 := m(1)^2 + m(2)^2 -r^2 ; u2 := 2m(1) and u3 := 2m(2)
u1 − a1u2 − a2u3 = −a1^2 − a2^2
u1 − b1u2 − b2u3 = −b1^2 − b2^2
u1 − c1u2 − c2u3 = −c1^2 − c2^2
m1 = u2/2 ,
m2 = u3/2
r =sqrt( m1^2 + m2^2 − u1)
How can i write the function and what shold i do?

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回答（2 个）

Image Analyst
Image Analyst 2021-6-20
Matt J
Matt J 2021-6-20
编辑：Matt J 2021-6-20
You can use circularFit() from this File Exchange submission
https://www.mathworks.com/matlabcentral/fileexchange/87584-object-oriented-tools-for-fitting-conics-and-quadrics
fitobj=circularFit([A(:),B(:),C(:)])

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