Add context menu when LEFT click on button (app design)

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Veronica Taurino
Veronica Taurino 2021-6-21
编辑： Johan C 2021-8-11
Hi!
I am trying to add kind of a context menu after LEFT pushing a button on a specific tab of my app, but it seems not to be allowed. Suggestion for a workaround?
I tried uicontextmenu and this link hint (and here) but nothing happens when I push the botton:
function ButtonAddPlotPushed(app, event)
cm = uicontextmenu(app.UIFigure); %
m1 = uimenu(cm,'Text','Menu1');
m2 = uimenu(cm,'Text','Menu2');
m3 = uimenu(cm,'Text','Menu3');
pos = app.ButtonAddPlot.Position(1:2)
set(cm,'Position',pos);
set(cm,'Visible','on');
end
My GUI is something like this:
I need something like this:
I can't use a toolbar instead, because I need it just below the "Output Visualization" tab, while the toolbar is added on the top of the app:
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Veronica Taurino
Veronica Taurino 2021-6-21
I tried a first workaround: I used a dropdown menu and I put a simple image above it. The dropdown works if the user click on the dropdown button area but if the user click on the small image, the dropdown menu does not open. I can't make it open with a callback either
Veronica Taurino
Veronica Taurino 2021-6-28
Is there a way to open the DROP DOWN menu by code? It would be enough to open it when clicking on the image as a callback, but I can't find a way

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回答（2 个）

Vimal Rathod
Vimal Rathod 2021-6-23
Hi,
You could try setting up 'HitTest' property of the Image to 'off' that way your UI could register its clicks and hopefully you could call the contextmenu.
Following link contains question similar to yours
How do I get the UICONTEXTMENU to appear on an image in my GUI that I created using GUIDE? - MATLAB Answers - MATLAB Central (mathworks.com)
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Veronica Taurino
Veronica Taurino 2021-6-28
编辑：Veronica Taurino 2021-6-29
Thank you for your answer! How can I implement this solution in the app design? I am not able to find the HIT TEST property on the Inspector or elsewhere, I was looking for something like that. How do I set it?

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Johan C
Johan C 2021-8-11
编辑：Johan C 2021-8-11
This work for me, hope it helps.
properties (Access = private)
cm % Description
end
function startupFcn(app)
% Create ContextMenu
app.cm.ContextMenu = uicontextmenu(app.UIFigure);
% Create Menu1
app.cm.Menu1 = uimenu(app.cm.ContextMenu);
app.cm.Menu1.Text = 'menu1';
% Create Menu2
app.cm.Menu2 = uimenu(app.cm.ContextMenu);
app.cm.Menu2.Text = 'menu2';
end
function ButtonPushed(app, event)
open(app.cm.ContextMenu ,event.Source.Position([1 2]))
end
Best JC

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