Create a generic matrix array (coordinates ) based on input data in a specific direction as attached in the photo

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sci hub 2021-6-21

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/861595-create-a-generic-matrix-array-coordinates-based-on-input-data-in-a-specific-direction-as-attached

编辑： Jonas 2021-6-22

Hi guys,

I am a bit new to matlab, tyring to generate generic matrix array coordinates (x,y).. I have tried the following code, but works in the wrong direction,

So can anyone help me .... with modifying the code, or so..

thank you,

clear all; 
clc; 
w=1;  b=1; m=2; n=2; 
dx = w/m;       dy = b/n;
tnod        =     (n+1)*(m+1);                                     % total number of nodes
co          =     zeros(tnod,3);
for ii = 1:m+1
    for jj  = 1:n+1
        node          =     jj + (ii-1)*(n+1);
        x(ii,jj)      =     (ii-1)*dx;
        y(ii,jj)      =     (jj-1)*dy;
        co(node,1)    =     x(ii,jj);
        co(node,2)    =     y(ii,jj);                               % CO not as I want 
    end
end
% CO result should be the following:
0      0      0
0.5    0      0
1      0      0
1      0.5    0
1      1      0
0.5    1      0
0      1      0
0      0.5    0
0.5    0.5    0

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Answer 1

Jonas 2021-6-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/861595-create-a-generic-matrix-array-coordinates-based-on-input-data-in-a-specific-direction-as-attached#answer_730315

编辑：Jonas 2021-6-22

在 MATLAB Online 中打开

here a quite manual solution, there may be something easier

width=2.8;
height=1.5;
pointsAlongY=4;
pointsAlongX=4;
dx = width/(pointsAlongX-1);
dy = height/(pointsAlongY-1);
tnod        =     (pointsAlongX)*(pointsAlongY);                                    
numberedGrid = zeros(pointsAlongY,pointsAlongX);
co=zeros(tnod,2);
currGridCoord=[1 pointsAlongY]; % x and y coordinate in grid
currRealCoord=[0 0];
currNode=1;
while 1
      numberedGrid(currGridCoord(2),currGridCoord(1))=currNode;
      co(currNode,:)=currRealCoord;
      currNode=currNode+1;
      % look if we are at the edges of the matrix or if the next entry is
      % unequal 0
      % we want to move right first, then up, left and down
      rightCondition=currGridCoord(1)~=pointsAlongX && numberedGrid(currGridCoord(2),currGridCoord(1)+1)==0;
      upCondition=currGridCoord(2)~=1 && numberedGrid(currGridCoord(2)-1,currGridCoord(1))==0;
      leftCondition=currGridCoord(1)~=1 && numberedGrid(currGridCoord(2),currGridCoord(1)-1)==0;
      downCondition=currGridCoord(2)~=pointsAlongY && numberedGrid(currGridCoord(2)+1,currGridCoord(1))==0;
      if rightCondition && ~downCondition
          currGridCoord(1)=currGridCoord(1)+1;
          currRealCoord(1)=currRealCoord(1)+dx;
      elseif upCondition
          currGridCoord(2)=currGridCoord(2)-1;
          currRealCoord(2)=currRealCoord(2)+dy;
      elseif leftCondition
          currGridCoord(1)=currGridCoord(1)-1;
          currRealCoord(1)=currRealCoord(1)-dx;
      elseif downCondition
          currGridCoord(2)=currGridCoord(2)+1;
          currRealCoord(2)=currRealCoord(2)-dy;
      else
          break;
      end
end
% there you can see how we went through the matrix
numberedGrid
% list of coordinates
co