defining arrays of structure

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AP 2011-6-1

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https://ww2.mathworks.cn/matlabcentral/answers/8623-defining-arrays-of-structure

In order to increase the speed of processing, I am trying to define an array of structures before proceeding to my main code, say, 100×50 arrays of the same structure. How can I define it beforehand?

struct('dir1',{},'dir2',{},'x1',{},'x2',{},'x3',{},'x4',{})

is the following correct?

n1=100;
n2=50;
data{n1,n2}=struct('dir1',{},'dir2',{},'x1',{},'x2',{},'x3',{},'x4',{})

Thanks a lot for your quick reply :)

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采纳的回答

Jan 2011-6-1

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https://ww2.mathworks.cn/matlabcentral/answers/8623-defining-arrays-of-structure#answer_11862

在 MATLAB Online 中打开

C = cell(100, 50);
S = struct('dir1', C, 'dir2', C ,'x1', C, 'x2', C, 'x3', C, 'x4', C);

Another method:

% S must be undefined before, otherwise use "clear('S')"
S(100, 50) = struct('dir1', [], 'dir2', [] ,'x1', [], ...
                    'x2', [], 'x3', [], 'x4', []);

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Jan 2011-6-1

@Ahmad: The S(100, 50)=struct() is 3 times faster. But we are talking about 0.1e-3 sec. I assume that reading this message will waste more time than using the worse method.

AP 2011-6-1