how to design a high-pass IIR filter having the transfer funciton ?

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Hi everyone,
i need to filter a signal with a high-pass IIR filter characterized by a transfer function as follow:
H(z) = 1-z^-1 / 1- a * z^-1
i know a = 0.995 and cut off frequency f = 0.25 Hz
i need to filter the sequence one time in forward direction and then in reversed.
Someone can help me ?
Thank you a lot :)

采纳的回答

Mathieu NOE
Mathieu NOE 2021-6-24
Here you are my friend
I don't know what sequence was supposed to be filtered , so the demo is on random signal
% IIr filter
fc = 0.25;
a = 0.995;
numd = [1 -1];
dend = [1 -a];
Fs = fc/(1-a)*2*pi;
% signal (random)
dt = 1/Fs;
samples = 3000;
t = (0:samples-1)'*dt;
x = randn(samples,1);
figure(1)
dbode(numd,dend,dt); % bode plot
y = filtfilt(numd,dend,x); % Zero-phase forward and reverse digital IIR filtering.
% y = filter(numd,dend,x); % forward digital IIR filtering.
figure(2) % time plot
plot(t,x,t,y);
legend('input signal','output signal');
  6 个评论
Giorgia Fusaroli
Giorgia Fusaroli 2021-6-24
Okok, i understood and thank you so much for the helping !
I'm trying to replicate a filter so fc = 0.25 and a = 0.995 and the transfer function were given to me.
The original filter is applied to a signal acquired at 200 Hz, this is why it doesn't work for me ?
And to work in my case, what and how should do i change the parameters of the filter ?
Mathieu NOE
Mathieu NOE 2021-6-24
well , now if fc and Fs are given , you can easily compute the a value :
a = 1 - 2*pi*fc/Fs;

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更多回答(1 个)

Giorgia Fusaroli
Giorgia Fusaroli 2021-6-24
编辑:Giorgia Fusaroli 2021-6-24
I have to day, the filter seems to only tranlsate the signal without modify it :(
  1 个评论
Mathieu NOE
Mathieu NOE 2021-6-24
no surprise
this is a low frequency high pass filter
it will only remove the mean (DC) value of the signal , which appears on your graph as a vertical shift; the "dynamic" portion of the signal remains unchanged as the filter has no effect above 0.25 Hz

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