could anyone help me how to convert double to cell in an array.

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jaah navi 2021-6-24

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/864600-could-anyone-help-me-how-to-convert-double-to-cell-in-an-array

评论： jaah navi 2021-7-16

采纳的回答： Matt J

I am having a cell array A in the folllowing manner

where A=3x1 cell

1x3 double - [1,1,1]

1x3 double - [1,2,2]

1x3 double - [1,1,2]

now, I want to convert A into B as given below

B=3x1 cell

1x1cell - [1,2,3]

1x2 cell -[1] [2,3]

1x2 cell - [1,2] [3]

i.e.,

A=3x1 cell to B=3x1 cell

1x3 double - [1,1,1] to 1x1cell - [1,2,3]

1x3 double - [1,2,2] to 1x2 cell -[1] [2,3]

1x3 double - [1,1,2] to 1x2 cell - [1,2] [3]

Could anyone please help me on this to do it on a general manner as my cell array size is larger.

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dpb 2021-6-24

To do anything in a "general" manner, there has to be some recognizable pattern that can be used as the basis for the algorithm -- what is the general rule here for an aribtrary size?

jaah navi 2021-6-25

the pattern for the algorthm is as follows:

A has all rows in double that needs to be converted as cell as shown in each rows of B.

In specific each rows of A has three values for example i am considering the first row of A 1x3 double - [1,1,1] .

Here as all the three values are 1 (in double), it need to be converted to cell as [1,2,3]

For 1x3 double - [1,2,2] the first value is 1 and the second and third value is 2. So to convert, the first value that corresponds to 1 should be [1] and the remaining two values corresponds to 2 should be [2,3].

For 1x3 double -[1,1,2] the first two values are 1 and the third value is 2. So to convert, the value corresponds to first two values should be [1,2] and the third value corresponds to 2 should be [3].

If my explanation is still not clear please let me know.Also please help me on this.

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Answer 1

Matt J 2021-6-24

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/864600-could-anyone-help-me-how-to-convert-double-to-cell-in-an-array#answer_732870

在 MATLAB Online 中打开

B=cell(size(A));
for i=1:numel(A)
    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
end

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Matt J 2021-6-25

在 MATLAB Online 中打开

I don't understand what you say you are seeing, but we can easily add some lines as below to display the output. It matches what you say you want.

A=[1 1 1 ; 1 2 2; 1 1 2]; A=num2cell(A,2);
B=cell(size(A));
for i=1:numel(A)
    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
    disp("A{" +i+ "}:"), A{i}
    for j=1:numel(B{i})
    disp("B{" +i+ "}{"+j+"}:"), B{i}{j}
    end
    disp ' '
end
A{1}:
ans = 1×3
     1     1     1
B{1}{1}:
ans = 1×3
     1     2     3
 
A{2}:
ans = 1×3
     1     2     2
B{2}{1}:
ans = 1
B{2}{2}:
ans = 1×2
     2     3
 
A{3}:
ans = 1×3
     1     1     2
B{3}{1}:
ans = 1×2
     1     2
B{3}{2}:
ans = 3
 

jaah navi 2021-7-16

在 MATLAB Online 中打开

Could you please help me how to modify the above code

B=cell(size(A));
for i=1:numel(A)
    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
    disp("A{" +i+ "}:"), A{i}
    for j=1:numel(B{i})
    disp("B{" +i+ "}{"+j+"}:"), B{i}{j}
    end
    disp ' '
end