Writing a function that stops after three odd numbers have been found in a list.

Question

Michael 2013-9-7

0
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https://ww2.mathworks.cn/matlabcentral/answers/86546-writing-a-function-that-stops-after-three-odd-numbers-have-been-found-in-a-list

I'm trying to write a script that will find the first three odd numbers in a list if there aren't three it should display "0". My current script determines if a single number is wrong but it doesn't go further than that.

function [ r ] = MyMod( x,y )
    while x >= 0
    x=x-y;
    end
    r=x+y;
    if r>0 disp('odd')
    end
end

Thanks for any help in advance.

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Answer 1

Youssef Khmou 2013-9-7

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https://ww2.mathworks.cn/matlabcentral/answers/86546-writing-a-function-that-stops-after-three-odd-numbers-have-been-found-in-a-list#answer_96040

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try to enhance this version :

 function Y=MyMod(X)
 %  List X
N=length(X);
Y=zeros(N,1); %  solution
ctr=1;   %  Counter
for t=1:N
    if mod(X(t),2)~=0
        Y(ctr)=X(t);
        ctr=ctr+1;
    end
end
Y=Y(1:3); %  First three
 if sum(mod(X,2))==0
    disp('0');
end

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Answer 2

Image Analyst 2013-9-7

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https://ww2.mathworks.cn/matlabcentral/answers/86546-writing-a-function-that-stops-after-three-odd-numbers-have-been-found-in-a-list#answer_96042

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I presume the implied question here is "How do I do it?" Here's one way:

% Create sample data
% Uncomment one of these
% m = [2 4 5 6 7 9 2 1 0] % Case with >3 odd #'s
m = [2 2 4 3 5 2] % Case where 0 should be displayed
% Now, find the first 3 odd values, displaying 0 if there are less than 3.
oddIndexes = find(mod(m, 2))
if length(oddIndexes) >= 3
  out = m(oddIndexes(1:3))
else
  out = 0
end