How to sort an array in descending order?

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vatankhah
vatankhah 2013-9-8
评论： Image Analyst 2017-12-7
For example with an array like X that is:
X=[10 3 6 8;
12 5 9 2;
66 4 7 11];
I want a code that gives me the total sort of array X in descending order:
sorted_X=[66 12 11 10;
9 8 7 6;
5 4 3 2];
thanks

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采纳的回答

Image Analyst
Image Analyst 2013-9-8
Try this:
[rows, columns] = size(X)
sorted_X = reshape(sort(X(:), 'descend'), [columns, rows])'
It gives you the exact result you showed. It sorts all the elements, regardless of what row or column they started in, then reshapes from a vector back into the shape of the original X matrix.

更多回答（3 个）

Markus
Markus 2013-9-8
Walter Roberson
Walter Roberson 2013-9-8
Do the total sort in ascending order, and then reverse the order of the elements.
venkatesh dixit
venkatesh dixit 2017-12-7
编辑：Image Analyst 2017-12-7
I have a matrix, and I have to keep the columns in ascending order of the sum of the matrix, or descending order or sum of matrix. Kindly tell how to do it. My matrix is as follows:
A=[1 3 3;
4 5 6;
9 18 17]
I have to sort it accordingly so that it becomes
[3 3 1;
6 5 4;
17 18 9];
  1 个评论
Image Analyst
Image Analyst 2017-12-7
Not clear at all. Are you sorting the first row somehow and applying the sort order to the other rows? If so, it's ambiguous because you have 3 in two locations. Like this:
[~, sortOrder] = sort(A(1,:), 'descend')
out = A(:, sortOrder)
Or are you summing horizontally to get the sum along each row, or vertically to get the sum along each column? It's just not clear at all. Please try to explain it more accurately.

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