Non-Overlapping Moving Sum

17 次查看(过去 30 天)
Consider any matrix, say Rain=(1:10)'. I want to compute a non-overlapping moving sum with two element.
Rain=1,2,3,4,5,6,7,8,9,10
Compute=1+2,3+4,5+6,7+8,9+10
With traditional movsum command, the moving sum is overlapping elements. I want to evaluate non-overlapping moving sum. Any in-built function? I have tried with loops and all those, it works but in-built function would be fast to compute.

采纳的回答

Star Strider
Star Strider 2021-6-27
Try this —
Rain = [1,2,3,4,5,6,7,8,9,10];
rRain = reshape(Rain, 2, [])
rRain = 2×5
1 3 5 7 9 2 4 6 8 10
sumRain = sum(rRain)
sumRain = 1×5
3 7 11 15 19
These could be combined into one line, however I kept them separate to demonstrate how it works.
.
  6 个评论
Star Strider
Star Strider 2021-6-27
@Matt J — Thank you! I didn’t think to look in FEX.
Suman Dhamala
Suman Dhamala 2021-6-27
This worked thanks @Matt J and everyone

请先登录,再进行评论。

更多回答(1 个)

Image Analyst
Image Analyst 2021-6-27
Since you have an image, you can do it with blockproc. However it only works with 2-D arrays so you'll have to do it once on each slice, then again along the z direction. I'm attaching some blockproc demos. I haven't done it with a 3-D image so you're on your own but I'm pretty sure it can be done.

类别

Help CenterFile Exchange 中查找有关 Introduction to Installation and Licensing 的更多信息

标签

产品


版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by