Transposing matrix of elements added by for loop

2 次查看（过去 30 天）

Kevin Burg 2021-6-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/866645-transposing-matrix-of-elements-added-by-for-loop

评论： DGM 2021-6-28

I am creating a matrix with 38 unique entries. My for loop is creating a 1x38 matrix but I need it to be 38x1 for the operation I'm trying to perform. I tried using transpose but that did not work. How would I transpose this matrix so that I get each element added as a new row instead of a column? This is occuring on the Sol.RHS matrix

for i=1:inds.numinds
for j=1:inds.ind_dat(i).nconn
        %
        % gather the properties on both sides
        %
        jind=inds.ind_dat(i).conn_array(j).ind;
        jsign=inds.ind_dat(i).conn_array(j).sign;
                     
        %
        % indices for implicit contribution
        %
        
        ivmm=inds.numind*ind_scale_eq + (jind - 1) + 1;
                
        %
        % add in implicit and explicit terms - vapor
        % 
        
        Sol.mat(ivmm,ivmm)=Sol.mat(ivmm,ivmm)+juns.jun_dat(jind).a*jsign/inds.ind_dat(i).volume;
        Sol.RHS(ivmm)=transpose(Sol.RHS(ivmm)+juns.jun_dat(jind).a*jsign*inds.ind_dat(jind).vv/inds.ind_dat(i).volume);
       
end
end

2 个评论
显示无隐藏无

Matt J 2021-6-28

I tried using transpose but that did not work

It doesn't seem possible that that would not work.

DGM 2021-6-28

How exactly did it not work? Since there really isn't any information here about the size of any of these variables, I have no idea what would happen. All anyone can go on is your assertion that one of them is 1x38 -- something that any troubleshooting should question if array size/orientation is not meeting expectations. You might want to provide enough data or pseudo-data such that your code constitutes a minimal working example of your problem.

请先登录，再进行评论。

请先登录，再回答此问题。