Need to Produce a different size matrix on each iteration

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DARLINGTON ETAJE
DARLINGTON ETAJE 2021-6-28
评论： DARLINGTON ETAJE 2021-6-28
Good Morning,
I need your urgent help. I have a presentation on this in a few hours. I am trying to create one matrix concatenated to the previous per loop.
the concept is that the abc first matrix is [1 51]. the second matrix is [1 51;2 52]; the third matrix is [1 51;2 52;3 53]; and so on.
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
abc=repmat({zeros(hsd,1)},hsd,1);
for i=1:hsd
kas(i)=wqe(i);
sak(i)=kli(i);
end
for h=2:1:hsd
abc{i}=[kas(i-1) sak(i-1);kas(i) sak(i)];
end

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采纳的回答

Alan Stevens
Alan Stevens 2021-6-28
Ran in:
Try the following
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
abc=zeros(hsd,2);
for i=1:hsd
kas(i)=wqe(i);
sak(i)=kli(i);
end
abc(1,:) = [kas(1) sak(1)];
for h=2:1:hsd
abc(h,:)=[kas(h) sak(h)];
end
disp(abc)
1 51 2 52 3 53 4 54 5 55 6 56 7 57 8 58 9 59 10 60 11 61 12 62 13 63 14 64 15 65
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Alan Stevens
Alan Stevens 2021-6-28
More like this?
wqe=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
kli=[51;52;53;54;55;56;57;58;59;60;61;62;63;64;65];
hsd=size(kli,1);
kas=zeros(hsd,1);
sak=zeros(hsd,1);
abc=zeros(hsd,2);
for i=1:hsd
kas(i)=wqe(i);
sak(i)=kli(i);
end
abc(1,:) = [kas(1) sak(1)];
for h=2:1:hsd
abc(h,:)=[kas(h) sak(h)];
end
matrix{1}=abc(1,:);
for i = 2:hsd
matrix{i}=abc(1:i,:);
end

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