Please try to format you question properly next time.
You want to know how many non-zero entries there are in each column I guess?
The easiest way of doing so is like this:
A=[0 0 0 0 0;0 1 1 0 0;0 1 0 0 0;0 1 1 0 0];
countPerColumn = sum(A==1,1);
% if you want to remove the zero entries you can add the following line:
countPerColumnRemovedZeros = countPerColumn;
countPerColumnRemovedZeros(countPerColumn == 0) = [];
If you want to adjust your own code (which is a bit sloppy in my opinion), you probably want something like this:
A=[0 0 0 0 0;0 1 1 0 0;0 1 0 0 0;0 1 1 0 0];
[rows, cols] = find(A == 1);
n1=min(cols); n2=max(cols);
m1=min(rows); m2=max(rows);
columns = n1:n2 ;
for ii=1:length(columns);
count=0;
for j=m1:m2
if A(j,columns(ii))==1
count=count+1;
end
end
count1(ii)=count;
end
