Comparing cell arrays for same values?

Ok so - This may be a little hard to explain to forgive me.
I have a selection of array of letters (lets call is matrix X), e.g
A B C; A C D; A D G; A E H; Q N J; A G K; A H I; A I W;
Defined as a 8x3 cell (in this case). I also have another array (matrix Y) (11x2 cell) of similar format (populated with letters).
What I want to do is write some code which looks through each row of matrix X in turn and returns a "1" if the row contains both letters in any row of matrix Y and a "0" if not.
For example, matrix X is as above and matrix Y is,
A F; E D; E C; J I; J H; M L; V T; V U; Q J; Q O; Q P;
In this case, the 5th row of matrix X would agree with the statement as "Q" and "N" are present (as in the 9th row of matrix Y). The other rows in X are all fine and would return "1".
I hope that makes sense - happy to explain further if necc.
Best,
Craig

2 个评论

You mean Q and J in the fifth row of X
Apologies - yes. thanks!

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Edit
X={'A' 'B' 'C'
'A' 'C' 'D'
'A' 'D' 'G'
'A' 'E' 'H'
'Q' 'N' 'J'
'A' 'G' 'K'
'A' 'H' 'I'
'A' 'I' 'W'}
Y={ 'A' 'F'
'E' 'D'
'E' 'C'
'J' 'I'
'J' 'H'
'M' 'L'
'V' 'T'
'V' 'U'
'Q' 'J'
'Q' 'O'
'Q' 'P'}
n=size(X,1);
out=zeros(n,1)
for k=1:n
out(k,1)=any(all(ismember(Y,X(k,:)),2))
end

1 个评论

That works nicely thanks. Think I have a few other tweaks to make to my overall project before I am done but this is very useful so thanks again!

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