清空筛选条件
清空筛选条件

how to create an array(1 by 5000) having random values in the range(9-11).

1 次查看（过去 30 天）
sanky kumar
sanky kumar 2013-9-10
i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

请先登录，再回答此问题。

采纳的回答

Image Analyst
Image Analyst 2013-9-10
编辑：Image Analyst 2013-9-10
Did you look in the help? It's example 1:
Example 1
Generate values from the uniform distribution on the interval [a, b]:
r = a + (b-a).*rand(100,1);
just change 100,1 to 1,5000, and change a to 9 and b to 11, like this:
r = 9 + 2 .* rand(1,5000);
By the way, what does "in sine" mean?
  2 个评论
sanky kumar
sanky kumar 2013-9-10
i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.
Image Analyst
Image Analyst 2013-9-10
编辑：Image Analyst 2013-9-10
I don't know if you mean that you want the random values to be the angle input to the sine,
out = sin(r);
or if you want to add those values to the sine wave:
x = linspace(0, 4*pi, length(r)); % Define angles.
noisy_y = amplitude * sin(x) + r;

请先登录，再进行评论。

更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-10
9+rand(1,5000)*2

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by