how to create an array(1 by 5000) having random values in the range(9-11).

Question

sanky kumar 2013-9-10

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/86790-how-to-create-an-array-1-by-5000-having-random-values-in-the-range-9-11

i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Attila 2013-9-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/86790-how-to-create-an-array-1-by-5000-having-random-values-in-the-range-9-11#answer_96325

在 MATLAB Online 中打开

Hi,

Use the uniform distribution function rand(), that outputs values between 0..1 and multiply the values by 2 and add the base 9:

uni = rand(1,5000)*2 + 9

2 个评论
显示无隐藏无

sanky kumar 2013-9-10

can i use this array as input for sine function? i guess we'll have some limitations please shed light on this issue

Attila 2013-9-10

编辑：Attila 2013-9-10

在 MATLAB Online 中打开

There are no limitations. As sine is a periodic function, you can input almost any value. It will return a vector with an identical shape as the input.

results = sin(uni)
plot(1:5000, results, 1:5000, uni)

Is this what you needed?

Edit: MATLAB encourages working with matrices instead of loops. Usually there is a workaround to avoid loops and most of the basic functions can accept vector inputs.

请先登录，再进行评论。