how to create an array(1 by 5000) having random values in the range(9-11).
1 次查看(过去 30 天)
显示 更早的评论
i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.
0 个评论
回答(1 个)
Attila
2013-9-10
Hi,
Use the uniform distribution function rand(), that outputs values between 0..1 and multiply the values by 2 and add the base 9:
uni = rand(1,5000)*2 + 9
2 个评论
Attila
2013-9-10
编辑:Attila
2013-9-10
There are no limitations. As sine is a periodic function, you can input almost any value. It will return a vector with an identical shape as the input.
results = sin(uni)
plot(1:5000, results, 1:5000, uni)
Is this what you needed?
Edit: MATLAB encourages working with matrices instead of loops. Usually there is a workaround to avoid loops and most of the basic functions can accept vector inputs.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!