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How to use effectively use the lazy quantifier for regular expression?

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Serbring
Serbring 2021-6-29
评论： Serbring 2021-6-30
Hi all,
I need to to set up a regular expression that stops at the first istance of the expression. To this goal, I am trying to use the lazy quantifier, unfortunately, with no success.
The input is '4223594459854' and the disidered output is {'4223594' '459854'}
Below you will find my code:
regexp('4223594459854','4.*4*?','match')
ans =
'4223594459854'
Which it does not stop at the first 4. How can I solve this issue?
Thank you so much.
Best regards.

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采纳的回答

Stephen23
Stephen23 2021-6-30
Ran in:
regexp('4223594459854','4.*?4','match')
ans = 1×2 cell array
{'4223594'} {'459854'}

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