Using function as arguments

2013 9 11
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I've just started to program and i've had some problems in passing function as arguments using Matlab. I've to implementate Lagrange Algorithm for interpolation. C1 and C2 are vectors that represent points to interpolate coordinates.
My main problem is that I don't know how to explain in my f1 definition that temp1 and temp2 are not variables but values determined on every for loop (for i and j). I think the code remaining part could be almost correct.
function [ ] = lagrange( C1,C2 )
n=length(C1);
f2=inline('');
g=inline('');
for i=1:n
temp0=C2(i);
temp1=C1(i);
for j=1:n
if (i~=j)
temp2=C1(j);
temp3=C2(j);
f1=inline('(x-temp2/(temp1-temp2)','x','temp1','temp2');
f2=f2.*f1
end
g=g+temp0*f2;
end
end
%plot g
end

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Azzi Abdelmalek
Azzi Abdelmalek 2013-9-11
编辑：Azzi Abdelmalek 2013-9-11

0 个投票

You can use
f=@yourfunction
Example
f=@cos
f(1)
Look at
doc function_handle
doc str2func

3 个评论
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Antonio
Antonio 2013-9-11
Thank you. I'll try now.
Antonio
Antonio 2013-9-11
编辑：Antonio 2013-9-11
I think i've not well explained my question because I think I don't need string control but it's first time for me that i program and i can not even explain well my problems. Having for example values for a and b, variables for each loop, i'd like to write a function only in x, for example, considering the second element of each vector i=2.
a=[0 0.25 0.5 1];
b=[1 5 3 7];
f(x)=x+a(i)+b(i);
I'd like that, at the end, for example at Loop i=2 the result'd be f(x)=x+5.25;
Azzi Abdelmalek
Azzi Abdelmalek 2013-9-11
This is not clear

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