using normrnd function in a loop
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If I use normrnd function in a loop, every times that normrnd runs in a new loop it will give me the same number? ( if I set parameters to a constant value);
for i = 1 :10
x(i) = normrnd(1,0.2);
end
采纳的回答
the cyclist
2013-9-12
0 个投票
No. It will give a different number on every call (until you reach the end of the pseudorandom generator's period, which is enormous).
更多回答（1 个）
Azzi Abdelmalek
2013-9-12
rng(14) % choose your seed
for i = 1 :10
x(i) = normrnd(1,0.2)
end
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