how i can limit the resistance(R) value within 1000 and 2000 ?

1 次查看(过去 30 天)
t = 0:0.0001:0.07;
v0 = input('please Enter the value for v0:');
R = input('please Enter the value for resistance:');
C = input('please Enter the value for capacitacne:');
f = input('please Enter the value for frequency:');
m = length(t);
state = 'on';
for A = 1:m
vs(A) = v0 * sin(2*pi*f*t(A));
switch state
case 'on'
vR(A) = vs(A);
iR = vR(A)/R;
iC = 2*pi*f*C*v0*cos(2*pi*f*t(A));
I = iC + iR;
if I<=0
state = 'off';
tA = t(A);
end
case 'off'
vR(A) = v0*sin(2*pi*f*tA)*exp(-(t(A)-tA)/(R * C));
if vs(A) >= vR(A)
state = 'on';
end
end
end
plot (t,vs,':',t,vR,'k')
thanks...
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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-15
Change the line
R = input('please Enter the value for resistance:');
by
R=0
while R<=1000 | R>=2000
R = input('please Enter the value for resistance: 1000<=R<=2000');
end

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